 |  |  | | | | |||||
 |
|  | | Two resistors in parellel
|
| | ||||
 |  |  | ||||||||
| | | | | | |||||
|  | | |  When two (or more) resistances are in parellel, then the resitence provided by the two together is given by reciprocal addition, i.e. 1/(total resistence) = (1/resistance1) + (1/resistance2).
| | |||||
| | | | | | |||||
| | | | | | |||||
| | |  The addition of reciprocals is a common solution for problems, aand this calc may be used to solve other similar relationships. For larger numbers of resistors, this calc may be used iteratively. | | ||||||
| | | | | | | | | ||
© Andy & Steve Shipway 2008